Jquery Aktif Pasif Buton (Mysql) | Cevap #1979

Arkadaşlar tekrar merhaba,
Sorunumu çözdüm, belki benim gibi acemi arakaşlarında bir gün işine yarar diye kodu yazıyorum.

<?php require_once('Connections/connect.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
if (PHP_VERSION < 6) {

$theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;

}

$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

switch ($theType) {

case "text":
  $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
  break;    
case "long":
case "int":
  $theValue = ($theValue != "") ? intval($theValue) : "NULL";
  break;
case "double":
  $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
  break;
case "date":
  $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
  break;
case "defined":
  $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
  break;

}
return $theValue;
}
}

mysql_select_db($database_connect, $connect);
$query_rapor = "SELECT * FROM rapor where id =84";
$rapor = mysql_query($query_rapor, $connect) or die(mysql_error());
$row_rapor = mysql_fetch_assoc($rapor);
$totalRows_rapor = mysql_num_rows($rapor);
?>

<!DOCTYPE html>
<html>
<head>

<title>Rapor Onay</title>
<script src="https://code.jquery.com/jquery-3.5.1.min.js" ></script>

</head>
<body>

<button type="button" id="buton" >Rapor yaz </button>

$sayi=<?php echo $row_rapor['durum']; ?>

deneme=($sayi);

if (deneme==1)

{
document.getElementById("buton").disabled = false;
}

else
{

document.getElementById("buton").disabled = true;

}
</script>

</body>
</html>
<?php
mysql_free_result($rapor);
?>